f(x) = |x| is shaped like a V with the vertex at the origin and the slope of each arm = 1. Then f(x) = |x + 3| will have the same shape but will be moved 3 units to the left so the vertex is at (-3,0). The - 1 ( to give f(x) = |x + 3| - 1) translates the whole graph 1 unit down so the vertex is at the point (-3, -1).
The domain is All Real x and the range = All real values of f(x)
The answer is C. Since 414 is an even number, it is divisible by 2. Since 115 ends in 5, it is divisible by 5. And 273 is divisible by 3 (if you add all the digits and that number is divisible by 3, so it the originals. 2+7+3=12 12/3=4)
