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lyudmila [28]
3 years ago
5

Can someone help me please this thrue me off big time

Mathematics
2 answers:
Ronch [10]3 years ago
8 0
Y = mx + n

m slope = Δy / Δx 

for point(-7,43) and (4,-12)

Δy = -12 - 43 = -55
Δx = 4 - (-7) = 11

m = - 55/11 =  -5

choose a point for instance point (-7,43) and insert it into the equation, you get:

43 = -5 * (-7) + n = + 35 + n

n = 43 - 35 = 8

so: 

y = -5x + 8


Elena-2011 [213]3 years ago
4 0
Slope = (-12 - 43)/(4 +7) = -55/11 = -5

y = mx + b
43 = -5(-7) + b
43=35+b
b = 8

equation
y = -5x + 8
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Suppose you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. If you randomly
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Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r}  ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 30

           r = number of success = at least 60%

           p = probbaility of success which in our question is the probability

                 of a correct answer, i.e; p = \frac{1}{4} = 0.25

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= \binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}

= 0.0000501

(b) The expected number of correct guesses is given by;

  Mean of the binomial distribution, E(X) =  n \times p

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(c) The standard deviation of the binomial distribution is given by;

      S.D.(X)  =  \sqrt{n \times p \times (1-p)}

                    =  \sqrt{30 \times 0.25 \times (1-0.25)}

                    =  \sqrt{5.625}  =  2.372                

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