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irinina [24]
3 years ago
6

Please help me I NEED HELP IT WILL BE QUICK 16 points

Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

1. 11^2

2. No

3. 18^2

4. 4^2

5. 9^2

6. No

7. 20^2

8. No

9. 15^2

Hope that helps! :)

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Solve each equation. Show your work<br><br> 13a=-5<br> 12−b=12.5<br> -0.1=-10c
amid [387]
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
5 0
3 years ago
What's the value of this expression ? 40-(3x2)x6
natita [175]
4

40-(3x2)x6
40-6x6
40-36
4
3 0
3 years ago
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Ashley found 2 boxes of sugar in the kitchen. The green box is 1.26 kg and the red box is 1.026 kg. Which box contains more suga
Anni [7]

Answer:

Answer:

Green box contains more sugar.

Step-by-step explanation:

Consider the provided information.

Ashley found 2 boxes of sugar in the kitchen.

The green box says 1.26 kg and the red box says 1.026 kg.

we need to find which box contains more sugar.

To find this we will first check the digit at ones place.

Both the digit has 1 at the ones place. So now check the digit at tenths place.

1.26 has 2 at tenths place while 1.026 has 0 at tenths place.

As we know 2 is greater than 0, thus the number 1.26 is greater than 1.026.

Hence, green box contains more sugar.

4 0
2 years ago
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Which equation could represent a circle with a center located at (11,-5)
Anon25 [30]
The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0
3 years ago
1. Solve for x.
kati45 [8]
This is the answer for the first one

7 0
2 years ago
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