What factors of 48 are multiples of 4

Logan's only debt obligations are a car loan payment of $512 and a credit card payment of $70 every month. What is the minimum a

Assoli18 [71]

The most used payment plan to avoid being in debt today is the 20% payment plan. In this payment , you divide your income into several parts.
20% for paying up debts, 10 % for savings, and 70% for everything else.

So, assuming that x is the minimum amount of money, we know that

$ 512 + $70 = 20% . X

$ 582 = 0.2 . x

$ 582 / 0.2 = x

x = $ 2910

3 0

3 years ago

Read 2 more answers

Solve the system using substitution: x = -4y and x + 5y = 2<br> Please and thank you.

Novay_Z [31]

Answer:

x = - 8, y = 2

Step-by-step explanation:

$x = - 4y......(1) \\ x + 5y = 2....(2) \\ plug \: x = - 4y \: in \: equation \: (2) \\ - 4y + 5y = 2 \\ y = 2 \\ plug \: y = 2 \: in \: equation \: (1) \\ x = - 4(2) \\ x = - 8\\$

7 0

3 years ago

At the end of January, Garrett had $176 in his

VikaD [51]

Answer:

bank account cant give me 5 bank name

4 0

3 years ago

The mean monthly car payment for 123 residents of the local apartment complex is $624. What is the best point estimate for the m

Natali [406]

Answer:

The best point estimate for the mean monthly car payment for all residents of the local apartment complex is $624.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this question:

We apply the inverse Central Limit Theorem.

The mean monthy car payment for 123 residents of the local apartment complex is $624.

So, for all residents of the local apartment complex, the best point estimate for the mean monthly car payment is $624.

3 0

3 years ago

How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$

5 0

3 years ago