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babymother [125]
3 years ago
13

At what point of the curve y = cosh(x does the tangent have slope 2?

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
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Viefleur [7K]

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First, multiply both sides of the equation by the reciprocal of h/2.

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Then, subtract b from both sides.

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