The hyperbolic cos (cosh) is given by cosh (x) = (e^x + e^-x) / 2 The slope of a tangent line to a function at a point is given by the derivative of that function at that point. d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x) Given that the slope is 2, thus sinh(x) = 2 x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
