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3 years ago

9

PLZZZZZZZZZZZZ PLZZZZZZZZZZZZ PLZZZZZZZZZZZZ HELP ASAP PLZZZZZZZZZZZZ NO LINKS PLEASE!!!

1 answer:

alex41 [277]3 years ago

3 0

Answer:

(.085 x 65) + 65 = $70.525 or $70.53 (if we rounding)

(5.525) + 65 =

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HELP PLEASE WILL GIVE BRAINLIEST

abruzzese [7]

Answer:
$1.21

Explanation:
What we know:
- $5.88=3 pounds of apples
- price went up by $0.75 per pound

First, we divide $5.88 by 3 to find out how much one pound of apples cost.

5.88/3
=1.96

Therefore, the new price of apples per pound is $1.96.

Because the old price of apples per pound was $0.75 cheaper, we subtract 0.75 from 1.96.

1.96-0.75
=1.21

Therefore, the old price of apples per pound was $1.21.

I hope this helps! Please comment if you have any questions.

7 0

3 years ago

Read 2 more answers

3. Milo's dog weighs 18.25 pounds. Kristen's dog weighs 2.5 pounds less than Milo's dog. How much does Kristen's dog weigh? (A)

il63 [147K]

Answer:

(B). 15.75

Step-by-step explanation:

If Kristens dog weighs 2.5 pounds less, then you just have to subrtact 2.5 from 18.25

7 0

2 years ago

Read 2 more answers

Define a variable and write an expression for the phrase.

kondaur [170]

n / 82 is your answer

5 0

3 years ago

Find the length of AB

ryzh [129]

Answer:

use the formula given in the pic and you will get the answer

3 0

3 years ago

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

3 years ago