PLEASE HELP AND EXPLAIN!!! (ASAP)
1 answer:
Let's look at the difference in speed between the two: it's 39-15.6=23.4 km/h
(we can just subtract this because they are traveling in the same direction) - this means that it's as if the slower train (the freight) was in place and the passenger train was traveling at 23.4 km/h
No, the freighter left 3.9 hours earlier, during which it traveled
15.6*3.9=60.84 km
So they will meet when the passenger train will catch up on those 60.84 km.
It does it with 23.4 km/h so it will need:
So the freighter will be travellinf for 2.6 more hours than the other train - a total of (2.6+3.9=6.5) 6.5 hours!
(we can just subtract this because they are traveling in the same direction) - this means that it's as if the slower train (the freight) was in place and the passenger train was traveling at 23.4 km/h
No, the freighter left 3.9 hours earlier, during which it traveled
15.6*3.9=60.84 km
So they will meet when the passenger train will catch up on those 60.84 km.
It does it with 23.4 km/h so it will need:
So the freighter will be travellinf for 2.6 more hours than the other train - a total of (2.6+3.9=6.5) 6.5 hours!
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simplifying a little bit,
looking for critical points,
We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.
When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.
Then apply your Zero-Factor Property,
and solve for x in each case to find your critical points.
Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.
Let's come back to this,
and take our second derivative.
Looking for inflection points,
Again, pulling out the smaller power of x, and fractional part,
And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.
Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.
simplifying a little bit,
looking for critical points,
We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.
When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.
Then apply your Zero-Factor Property,
and solve for x in each case to find your critical points.
Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.
Let's come back to this,
and take our second derivative.
Looking for inflection points,
Again, pulling out the smaller power of x, and fractional part,
And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.
Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.