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2 years ago

Matchhhhhh themmmmmmmmmm?

Mathematics

1 answer:

umka21 [38]2 years ago

7 0

Answer:

My answer

Step-by-step explanation:

Matching the two set of variables:

1) Contains two outliers

2) Contains no outliers

3) Contains one outlier

4) Contains three outliers

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A smoke jumper jumps from a plane that is 1700 ft above the ground. The function y = -16t2 + 1700 gives the jumper's height y in

lakkis [162]

Answer: (A) 6.6 sec (B) 6.89 sec

Step-by-step explanation:

y = -16t² + 1700

1000 = -16t² + 1700

-1700 -1700

-700 = -16t²

÷-16 ÷-16

43.75 = t²

√43.75 = √t²

6.6 = t

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y = -16t² + 1700

940 = -16t² + 1700

-1700 -1700

-760 = -16t²

÷-16 ÷-16

47.5 = t²

√47.5 = √t²

6.89 = t

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2 years ago

my mum was 27 when I was born,8 years she was twice as old as I shall be in 5 years time. how old am I now?

jeyben [28]

Answer:

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Step-by-step explanation:

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2 years ago

Given that 'n' is any natural numbers greater than or equal 2. Prove the following Inequality with Mathematical Induction

Oliga [24]

The base case is the claim that

$\dfrac11 + \dfrac12 > \dfrac{2\cdot2}{2+1}$

which reduces to

$\dfrac32 > \dfrac43 \implies \dfrac46 > \dfrac86$

which is true.

Assume that the inequality holds for n = k ; that

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k > \dfrac{2k}{k+1}$

We want to show if this is true, then the equality also holds for n = k + 1 ; that

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2(k+1)}{k+2}$

By the induction hypothesis,

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2k}{k+1} + \dfrac1{k+1} = \dfrac{2k+1}{k+1}$

Now compare this to the upper bound we seek:

$\dfrac{2k+1}{k+1} > \dfrac{2k+2}{k+2}$

because

$(2k+1)(k+2) > (2k+2)(k+1)$

in turn because

$2k^2 + 5k + 2 > 2k^2 + 4k + 2 \iff k > 0$

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