Ask question

Ask question

All categories

nataly862011 [7]

3 years ago

7

What is the answer to -2 3/4 ÷ 5/-9 ??

2 answers:

kolbaska11 [484]3 years ago

7 0

Answer:23 /180

Step-by-step explanation:

−23/ 4 /5 /−9= 23 /180

sergiy2304 [10]3 years ago

5 0

Answer: 99/20

Step-by-step explanation:

-2 3/4 / 5/-9

-11/4/5/9

11/4*5/9

99/20

You might be interested in

15 cm<br> 4 cm<br> cm<br> V=____cm3

bonufazy [111]

Answer:

V=(πr^2 x h)/3

lets use π as 3.14 cause I dont know what pi u using

3.14 x 4^2 x 15 = 753.6/3 = 251.2

If you're using π as your pi, than just replace 3.14 by π on calculator

Hope that answers your question

8 0

3 years ago

11 times 12 equals 10 plus 1 times 10 + 2 what property does this demonstrates

pochemuha

The answer is 144 but I do not know the property

8 0

3 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em> $p(x)$ <em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em> $p(x)=x^4-9x^2-4x+12$ <em> and will solve the question based on this assumption expression of </em> $p(x)$ <em>, which anyways would solve your query.</em>

Answer:

As

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

As

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say<em> </em> $p(x)$ <em>, </em> $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ <em>, </em>we must have to evaluate <em> </em> $p(x)$ <em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0$

$\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=2^4-2^2\cdot \:9+8+12$

$=2^4+20-2^2\cdot \:9$

$=16+20-36$

$=0$

Thus,

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Now, solving for $p\left(2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12$

$p\left(2\right)=2^4-2^2\cdot \:9-8+12$

$p\left(2\right)=2^4+4-2^2\cdot \:9$

$p\left(2\right)=16+4-36$

$p\left(2\right)=-16$

Thus,

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Keywords: polynomial, root

Learn more about polynomial and root from brainly.com/question/8777476

#learnwithBrainly

7 0

3 years ago

Read 2 more answers

Solve for x The value of x is

Varvara68 [4.7K]

Answer:

7x+19 = 11x-89

-19. -19

7x= 11x-108

-11x -11x

-4x=-108

x=27

8 0

3 years ago

Which ordered pair is in the solution set of the system of linear inequalities graphed below?

motikmotik

Answer:

Graphed?

Step-by-step explanation:

5 0

3 years ago