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Vesna [10]
3 years ago
10

What is the average rate of change of f(x), represented by the graph, over the interval [0, 2]?

Mathematics
2 answers:
max2010maxim [7]3 years ago
8 0

Answer:

a it is 2

Step-by-step explanation:

zloy xaker [14]3 years ago
4 0

Answer:

The average rate of change of f(x) is 2

A is correct

Step-by-step explanation:

Given: The graph of f(x).

To find: Average rate of change of f(x) in interval [0,2]

Formula:

\text{Average rate }=\dfrac{f(b)-f(a)}{b-a}

Using graph, we find f(0) and f(2)

a = 0 , b= 2

f(0) = 4

f(2) = 8

\text{Average rate } = \dfrac{f(2)-f(0)}{2-0}

\text{Average rate } = \dfrac{8-4}{2-0}

                                 = 2

Hence, The average rate of change of f(x) is 2

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irina [24]

Answer:

So the intermediate step in question is (x - 10)² = 66

Step-by-step explanation:

Let's find out:

x² + 34 = 10x

x² - 10x = -34

x² - 20x + 100 = 66

(x - 10)² = 66

x - 10 = ± √66

x = 10  ± √66

x ≈ 18.12, 1.88

5 0
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Ira Lisetskai [31]

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Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary. ​
svetlana [45]
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Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
This is a fraction so whats 1/2 x 7/9
zhuklara [117]

Answer:

7/18

Step-by-step explanation:

3 0
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