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2 years ago

How do you know your GPA base on your grade this year?

Mathematics

1 answer:

guapka [62]2 years ago

6 0

Answer:

Obtain semester GPAs. Obtain the semester GPA for all semesters in school. ...

Add the numbers. Add all semesters and make note of the total.

Divide by semesters. Take the sum of all of your semesters and divide it by the number of semesters in school. ...

Get the result.

Step-by-step explanation:

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Which graph represents a line function?

UkoKoshka [18]

Answer:

there's one graph I don't see the others

5 0

2 years ago

A painter earns $15 per hour.What is the minimum number of hours he must work to earn at least $200?

umka21 [38]

Let's represent h with the number of hours:

15h ≥ 200

h ≥ 200/15

h ≥ 40/3

h ≥ 13 1/3

He has to work at least 13 1/3 hours.

4 0

3 years ago

I will give 98 points,brainlyiest,5 stars,and a like to who ever answers or gets right. what i the absolute value of of point B

Alex777 [14]

There are 5 little lines between 0 and -1, so each line represents 1/5.

B is located 3 lines to the left of -1, so it would be located at - 1 3/5.

Am absolute value is a positive number so - 1 3/5 would become 1 3/5.

The answer would be A. 1 3/5

5 0

2 years ago

Read 2 more answers

What is the common ratio of the sequence -2,6,-18,54

sdas [7]

Common ratio, r is found by dividing the next term by the previous term

r = $\frac{6}{-2}$ = -3
you can see this value is true for any consecutive pairs of terms
also, multiply by -3 to get the next term

8 0

3 years ago

2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.

Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by $h(t)= -16t^2+15t + 12$

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled $h(t)= -16t^2+15t + 12$ ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

$h'= -32t+15$

For critical point put h'=0,

$-32t+15=0$

$t=\frac{15}{32}$

$t=0.46875$

Derivate again w.r.t. t,

$h''= -32$

It is maximum at t=0.46875.

Substitute t in equation (1),

$h(0.46875)= -16(0.46875)^2+15(0.46875)+12$

$h(0.46875)= -3.515625+7.03125+12$

$h(0.46875)= 15.515625$

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

$-16t^2+15t + 12=0$

Apply quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=-16 , b=15, c=12

$t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}$

$t=\frac{-15\pm\sqrt{225+768}}{-32}$

$t=\frac{-15\pm\sqrt{993}}{-32}$

$t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}$

$t=−0.515,1.453$

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

5 0

3 years ago