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3 years ago

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Owen settled on a price of $7,870 for a new car. The dealer had to add 4.5% sales tax to this price, but allowed a $1,200 trade-

in for Owen's old car. Although not a universal practice, please add the sales tax to the price of the new car first and then deduct the trade- in value. If the dealer required a 15% down payment, calculate the amount of the purchase price that Owen financed.

1 answer:

kakasveta [241]3 years ago

4 0

Multiply the numbers by the percent but first convert the percent into a decimal then after u multiply add that number to the tottal

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Find the difference in simplest form for 3/5-1/7

morpeh [17]

Answer: 0.457

multiply 3 by 7, and get 21

multiply 1 by 5, and get 5.

5 × 7 = 35.

fraction: 21/35 and 5/35

Subtract the numerators

21 − 5 = 16 = 16/35

Now we need to simplify the fraction that we have.

17 is larger than 16. So we're done reducing numbers.

<em>Our final answer: </em> $16/35$ <em />

Hope this helps!

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3 years ago

Drag each tile to the correct box.

kolbaska11 [484]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 unitsb) Distance between points E (-2, -1) and F( -2, -5) is 4 unitsc) Distance between points C (-4, 1) and D( 1, 1) is 5 unitsd) Distance between points G(3, -5) and H(6, -5) is 3 unitsStep-by-step explanation:We need to find the distance between each paira) A (5, 4) and B( 5, -2)

Step-by-step explanation:

8 0

3 years ago

Can someone help me answer questions

ANEK [815]

Add 6 to both sides
2m2+7m+6=0

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3 years ago

What is the slope of the line passing through the points (7, 10) and (5, 16) ?<br> Thank you

butalik [34]

Answer:

m=-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=16-10/5-7

m=6/-2

m=-3

4 0

2 years ago

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BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

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