Quadratic eq standard form is
Ax^2+bx+c=0
<span>a, b and c are known values.
a can't be 0.</span><span>"x" is the variable
lets take an example
</span><span>x^2 − 4x+2 = 0
</span><span>
x^2-2x-2x+2=0
x(x-2) - 1(x-2)=0
x=1,2
</span>
20y-6y-15
=14y-15 is the answer
Answer:
Step-by-step explanation:
The equation of the table of values given can be written as .
When x = 0,
this corresponds with what we have in the table above.
Let's try another.
When x = 2,
This also corresponds with what we have in the table.
Therefore, the equation of the table given is .
10x^4y^3 - 5x^3y^2 + 20x^2y....first, find the GCF of ur coefficients (numbers)....it is 5...now find the lowest exponents of x, which is x^2...and now find ur lowest exponent of y, which is y
so ur GCF is : 5x^2y
