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vagabundo [1.1K]
3 years ago
11

12. A road race is 15 kilometers long. After the starting line, there are water stations every

Mathematics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

50

Step-by-step explanation:

Given

there is 1 water station at every 0.3 KM

If there are n water stations at every 0.3 KM

then KM covered by them = n*0.3 = 0.3n

given that total KM covered is 15 km

Thus,

0.3n = 15

=> n = 15/0.3 = 50

Thus, there are 50 water stations.

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What is 2 times 2/6?
Aloiza [94]

Hi there!


I can see why you've posted a question like this here - For adding, subtracting, multiplying, or dividing fractions by whole numbers can be difficult to come out with a precise answer, so let me make it look easier for you!


So, the steps are:


Smush the 2 (whole number) and the 2 (the numerator of the fraction) together on top so its (2)(2) over 6. I can show you what I mean, if you'd like.


\frac{(2)(2)}{6} This is what it should look like.


Now, what is 2 times 2? You can use a calculator for this part.


2 *2 = 4


Now, we can get to the last part, my favorite one!


Simplify \frac{4}{6} down to \frac{2}{3}.


How did we do it? EASY!


See what number does evenly into both numerators and denominators. In this case, 2 goes into 4 twice, and 2 goes into 6 three times, so we're left with our beautiful answer \frac{2}{3}.


That wasn't so bad, was it? You can use this as a guide for figuring out math problems like these, in case you're stuck again. But just in case, message me if you need anymore help! :D

4 0
3 years ago
Read 2 more answers
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.
Firdavs [7]

Answer:

New can holds 112.25\,\,cm^3 more than the old can

Step-by-step explanation:

Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is 339.12\,\,cm^3

Dimensions of the can are increased by a multiple of 1.10

To find: Difference between the volume of new can and volume of old can

Solution:

Volume of can (v) = 339.12\,\,cm^3

Let r, h denote radius and height of the can.

Let R, H denotes radius and height of the new can.

r = diameter/2 = \frac{6}{2}=3\,\,cm

h = 12 cm

R = 3(1.1)=3.3.\,\,cm

H = 12(1.1)=13.2\,\,cm

New volume (V) = \pi (R)^2H=\pi(3.3)^2(13.2)=451.37\,\,cm^3

So,

V-v=451.37-339.12=112.25\,\,cm^3

7 0
3 years ago
Help me with math question please, will give 20 points
Kisachek [45]

in step 2 he made his first mistake

1/2(n-4)-3=3-(2n+3)

1/2n-4/2-3=3-(2n+3)

1/2n-2-3=3-(2n+3)

in the second step he put 5 instead of 2.

5 0
3 years ago
58 is 20% of<br>having trouble
ella [17]
First, let's introduce a variable:

Let n represent the number we are trying to find.

20 % x n = 58
0.20 x n  = 58
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Hope this helps!
Message me if you have any questions. :)
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Determine if 1.7 is a solution to r- 2.4 &lt; 5
notsponge [240]

esuerate  lograras loysf

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