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Brilliant_brown [7]
3 years ago
15

What is the f of x over the g of x when f(x)=6x^3-19x^2+16x-4 and g(x)=x-2?

Mathematics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

no four is not better than 7679_727=2873

Step-by-step explanation: 89 is 48-23

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40 points Please help, answer and explain, please. Thank you!
zaharov [31]

Answer:

<h2>C. 6x² + 6x² + 3x + 4</h2>

Step-by-step explanation:

6x^2-2x^4+4+3x\\\\\text{Look at the power of variables.}\\\text{Arrange the terms in order from the largest exponent to the smallest.}\\\\-2x^4+6x^2+3x+4

6 0
3 years ago
If θ = 330° and α = 300°, find the exact value of tan θ − sin α.
Vilka [71]
X = tan (330) - sin (330)
x = 0.133557089 - -0.132381629
x = 0.133557089 + 0.132381629
x = 0.265938718
7 0
3 years ago
Match each equation with its solution set.
taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

 magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

OR

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

OR

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

OR

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I  I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

OR

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I  I never give negative answer

* The solution of Ix - 3I = -12 is ∅

4 0
3 years ago
Between which two tenths is the decimal approximation of √7?
RUDIKE [14]

Answer:

2.6 and 2.7

Step-by-step explanation:

The actual square root of 7 is 2.64 and that is between 2.6 and 2.7.

4 0
2 years ago
) A coin collection consisting of pennies, dimes, and quarters totals 45 coins. The number of
Sloan [31]

9514 1404 393

Answer:

  $7.14

Step-by-step explanation:

Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.

  p + d + q = 45 . . . . . . . . there are 45 coins in the collection

  2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies

  p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies

Substituting the last two equations into the first gives ...

  p +(p +4) +(2p +5) = 45

  4p = 36 . . . . . . . . . . . . . subtract 9

  p = 9 . . . . . . . . . . . divide by 4

  d = 9 +4 = 13

  q = 2(9) +5 = 23

The value of the collection is ...

  23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14

The coin collection is worth $7.14.

5 0
3 years ago
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