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Elden [556K]
3 years ago
6

How can a translation and a reflection be used to map ΔHJK to ΔLMN? Translate K to N and reflect across the line containing HJ.

Translate K to N and reflect across the line containing JK. Translate H to L and reflect across the line containing JK. Translate K to L and reflect across the line containing HJ.

Mathematics
2 answers:
aliya0001 [1]3 years ago
9 0

Answer:

Its B on ED2020

Step-by-step explanation:

Svet_ta [14]3 years ago
3 0

Answer:

<u>Translate K to N and reflect across the line containing JK. </u>

Step-by-step explanation:

The rest of the question is the attached figure.

From the figure, we can deduce the following:

∠K = ∠N

JK = MN

HK = LN

So, N will be the image of K

By translating K to N, The segment JK will over-lap the segment MN,

Then, we need to reflect the point H across the the line containing JK to get the point L

So, the translation and a reflection that will be used to map ΔHJK to ΔLMN:

<u>Translate K to N and reflect across the line containing JK. </u>

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Which could be the area of a face of the rectangular prism? A rectangular prism with a length of 3 meters, width of 4 meters, an
blagie [28]

Answer:

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Step-by-step explanation:

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3m x 4m = 12m²

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5 0
3 years ago
What is the sum of the first 7 terms of the geometric series:
Fiesta28 [93]

Answer:

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Step-by-step explanation:

First, we can sum up the first 5 terms.

-8 + (-4) = -12

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Next, we can find a pattern in the data. We can tell that the next number is one half of the current number. For example, -4 is one half of -8. To find the next number, we simply multiply our current number by one half. Thus, the sixth number is -1/4 and the seventh is -1/8. Adding these to our current total, we have

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4 0
3 years ago
HELLPP ASAP!!!What are the exact solutions of x2 − 5x − 1 = 0 using x equals negative b plus or minus the square root of the qua
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Answer: x = the quantity of 5 plus or minus the square root of 29 all over 2

Step-by-step explanation:

The given quadratic equation is expressed as

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The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the given quadratic equation,

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x = [5 ± √29]/ 2

x = ( 5 + √29)/- 2 or x = (5 - √29)/2

6 0
3 years ago
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