Answer:
the value of the series;

C) 59
Step-by-step explanation:
Recall that;

Therefore, we can evaluate the series;

by summing the values of the series within that interval.
the values of the series are evaluated by substituting the corresponding values of k into the equation.

So, the value of the series;

Answer:
4.) = 1.57
5.) = 3.93
Step-by-step explanation:
Answer:
The equation of a line in the slope-intercept form is:
y = 5x - 18
The slope-intercept form of the line equation
where
m is the slope
b is the y-intercept
In our case, we are given
m = 5
Point (4, 2)
now substituting m = 5 and (4, 2) in the slope-intercept form of the line equation to determine the y-intercept
y = mx + b
2 = 5(4) + b
20 + b = 2
subtract 20 from both side
20 + b - 20 = 2 - 20
b = -18
now substituting b = -18 and m = 5 in the slope-intercept form of the line equation
y = mx + b
y = 5x + (-18)
y = 5x - 18
Therefore, the equation of a line in the slope-intercept form is:
y = 5x - 18
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