Question

I need help on this problem??

Answer 1

Answer:

  {120°, 420°, 480°, 780°, 840°}

Step-by-step explanation:

From your knowledge of the short table of trig functions, you know that ...

  sin(60°) = (√3)/2

and that the sine of the supplement of this angle has the same value. Of course, the sine function is periodic with period 360°, so the solutions will all be of the form ...

  θ = 90° ± 30° + k·360°

for any integer k.

For the range of interest, the angles are ...

  90° +30° = 120°

  360° +90° -30° = 420°

  360° +90° +30° = 480°

  2·360° +90° -30° = 780°

  2·360° +90° +30° = 840°