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Tanzania [10]
2 years ago
13

The histogram shows the distributions of essay scores for high school sophomores and juniors in a contest. Which comparison of t

he distributions is true? Both distributions are nearly symmetric. Both distributions are right-skewed. The distribution of sophomores’ scores is right-skewed, and the distribution of juniors’ scores is left-skewed. The distribution of sophomores’ scores is left-skewed, and the distribution of juniors’ scores is right-skewed.

Mathematics
2 answers:
goblinko [34]2 years ago
8 0

Answer:

A=Both distributions are nearly symmetric

Step-by-step explanation:

Mariulka [41]2 years ago
8 0

Answer:

A.

Step-by-step explanation:

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Suppose two random variables, X and Y are independent, which statement is false? a) P(X∣Y)=P(X) b) P(X∪Y)=P(X)+P(Y) c) P(X∩Y)=P(
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B is false, since by the inclusion/exclusion principle,

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2 years ago
Please help me!! I don’t know how to do this
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3 years ago
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lesya [120]

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4 0
2 years ago
Y 65° 25 <br>can someone solve this ? ​
n200080 [17]
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7 0
3 years ago
Rachel has 60 scones. She sells them to Robbie, Cameron, Louis, Tom and
Nutka1998 [239]
We can start by writing all that we know about the problem. Let us write down how many scones each boy has:
R_{o} : x
C_{a} : x+k
L_{o} : x+2k
T_{o} : x+3k
C_{h} : x+4k
Note that k is the increase, we know it's a constant. This is not a system of equations, please keep that in mind. We will use rest of the information given to build the system. We have two variables x (the number of cookies the first boy bought) and k( the increase), that means we need to have two equations to solve this problem. 
We know that total amount of scones is 60, so we can use that information to build our first equation. We sum all of the scones and we get 60. 
R_{o}+C_{a}+L_{o}+T_{o}+C_{h}=60
5x+10k=60
We know that Robbie and Cameron combined have 3/7 of <span>Louis, Tom and Charlie combined. We can use this information to build our second equation.
</span>R_o+C_a= \frac{3}{7} (L_o+T_o+C_h)
2x+k= \frac{3}{7} (x+2k+x+3k+x+4k)
2x+k= \frac{3}{7} (3x+9k)
14x+7k=9x+27k
5x=20k
x=4k
Now this piece of information alows us to solve the first equation that we made and this will solve our problem. We simply plug in x=4k into 5x+10k=60.
5(4k)+10k=60
30k=60
k=2
Now we can plug this information into the same equation 5x+10k=60 and get x.
5x+10(2)=60
5x=40
x=8
And that's it. Now we can write out how many cookies each boy has bought.
R_{o} : x=8
C_{a} : x+k=10
L_{o} : x+2k=12
T_{o} : x+3k=14
C_{h} : x+4k=16
If you add them all up you get 60.
3 0
2 years ago
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