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laila [671]
3 years ago
13

A(n) _____ generally has a highly elliptical orbit. A. moon B. comet C. planet D. asteroid

Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0

Answer:

b

Step-by-step explanation:

Arisa [49]3 years ago
5 0

Answer:

B comet

Step-by-step explanation:

Orbit of a Comet. Comets go around the Sun in a highly elliptical orbit. They can spend hundreds and thousands of years out in the depths of the solar system before they return to Sun at their perihelion. Like all orbiting bodies, comets follow Kepler's Laws - the closer they are to the Sun, the faster they move.

Please BRAINLIEST!

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a standard 35-mm movie projects 24 images each second. at this rate, how many images are necessary for a 1.5 hour movie ?
yuradex [85]
129,600. 60 seconds in a minute, 60 minutes in an hour 60x60=3600, so 3600 seconds=1 hour. 1800 seconds = half hour. 3600 + 1800 = 5400 seconds in 1.5 hours. 5400 x 24 = 129,600. Hence, 129,000 images are necessary for a 1.5 hour movie.

Hope this helps!
Have a nice day :)
-fart2fart
3 0
3 years ago
Solve for the value of X. <br> -4x + 3 = 35
Stella [2.4K]

Answer:

-8

Step-by-step explanation:

4 0
3 years ago
Whats the product of (-3x+2y)(4x-y)
oee [108]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If I have the full price of an item, &amp; the discounted price of the same item, how do I find the discount percentage?
melamori03 [73]

Answer:

Subtract the discount price from the full price. Divide the amount of change by the original price.

Step-by-step explanation:

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5 0
3 years ago
Radical expression of 4d 3/8
DanielleElmas [232]

Answer:

\boxed{4 \sqrt[8]{ {d}^{3} } }

Step-by-step explanation:

=  > 4 {d}^{ \frac{3}{8} }   \\  \\ =   > 4({d}^{3 \times  \frac{1}{8} }) \\  \\  =  > 4( {d}^{3}  \times   {d}^{ \frac{1}{8} } ) \\  \\  =  > 4( {d}^{3}  \times  \sqrt[8]{d} ) \\  \\  =  > 4  \sqrt[8]{ {d}^{3} }

8 0
2 years ago
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