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Snezhnost [94]
3 years ago
12

3 and 5/6 times 1 and 2/4

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:  23/4

Decimal form= 5.75

Mixed Number Form= 5 and 3/4

The Answer is 23/4

Step-by-step explanation: Hope this helps please mark me brainlest

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A pipe is leaking at 1.5 cups per day. About how many gallons per week is the pipe leaking? (Hint: 1 gallon = 16 cups)
Vesnalui [34]

Answer:

.65625 gallons a week

Step-by-step explanation:

1.5 x 7=10.5

10.5/16= .65625

4 0
3 years ago
Read 2 more answers
Will mark brainliest!
FrozenT [24]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Find the multiplier : 15/100 = 0.15

Multiply by the original

150 x 0.15 = 22.5

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0
3 years ago
Help fast please !! Represent the following sentence as an algebraic expression, where "a number" is the letter x. 4 is added to
Oduvanchick [21]
The answer is 2x + 4 :)
5 0
3 years ago
What are the answer and how do i solve it
Shkiper50 [21]
I'll answer 3 of these questions. 
For future notice, make sure to limit yourself to asking at most, 3 individual questions per question. :)

1) r/10+4=5
Subtract both sides by 4.
(r/10+4)-4=(5)-4
r/10=1
Multiply both sides by 10.
(r/10)*10=(1)*10
r=10

2) n/2+5=3
Subtract 5 from both sides.
(n/2+5)-5=(3)-5
n/2=-2
Multiply both sides by 2.
(n/2)*2=(-2)*2
n=-4

3) 3p-2=-29
Add 2 to both sides.
(3p-2)+2=(-29)+2
3p=-27
Divide both sides by 3.
(3p)/3=(-27)/3
p=-9

Hope this helps.
-Benjamin


4 0
4 years ago
What is the interquartile range of the data? 24, 25, 27, 36, 37, 42, 42, 43, 49, 49, 50, 53, 59, 61, 65 41 7 17 10
AysviL [449]
<span>The interquartile range is the difference between the third quartile and the first quartile. First, find the median so you can separate the data in half. The median is the middle number. Arrange the numbers from least to greatest and find the number in the middle.

</span>\sf 24, 25, 27, 36, 37, 42, 42, \boxed{\sf 43}, 49, 49, 50, 53, 59, 61, 65

Find the medians of these two halves. These will be Quartile 1 and Quartile 3.

\sf 24, 25, 27, \boxed{\sf 36}, 37, 42, 42

Quartile 1 is 36

\sf 49, 49, 50, \boxed{\sf 53}, 59, 61, 65

Quartile 3 is 53

\sf IQR=Q3-Q1=53-36=\boxed{\sf 17}
3 0
3 years ago
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