4(x−2+y)<br> It's for khan academy

Jack picked 76 apples. Of these, he sold 4y apples to Juanita and 3t apples to Sylvia. If he kept the remaining apples, how many

Alex Ar [27]

Answer:

Number of apples remaining with him will be 2 when we combined both the conditions.

Step-by-step explanation:

Given;

Number of apples Jack Picked =76

Number of apples sold to Juanita = 4y

Number of apples sold to Sylvia = 3t

We need to find the Number of apples remaining with him.

Solution:

To find the Number of apples remaining with him we will Subtract Number of apples sold to Juanita and Number of apples sold to Sylvia from Number of apples Jack Picked.

framing in equation form we get;

Number of apples remaining with him = $76-4y-3t$

Now Given:

Condition 1 : y ≥ 15 and t = 2

So we can assume y =16 and t =2

Number of apples remaining with him = $76-4\times16-3\times2 = 76 -64 -6 = 6$

Also we can say that y =17 and t =2

Number of apples remaining with him = $76-4\times17-3\times2 = 76 -68 -6 = 2$

So the Given data is Insufficient to find the Number of apples remaining with him.

Condition 2 : y = 17

Number of apples remaining with him = $76-4\times17-3t = 76 -68 -3t = 8-3t$

Since value of t is not given we can say that;

Given data is insufficient to find the number of apples remaining with him.

Condition 3 : Combined i.e y = 17 and y≥ 15 t = 2

Number of apples remaining with him = $76-4\times17-3\times2 = 76 -68 -6 = 2$

Hence we can say that Number of apples remaining with him will be 2 when we combined both the conditions.

7 0

3 years ago

Please help me asap

Arada [10]

Answer:

See explanation

Step-by-step explanation:

Car A: Started at 0 and ended at 300, thus, car A travels 300 miles.

It travels 6 hours, so car A speed is $\frac{300}{6}=50$ mph.

Car B: Started at 100 and ended at 300, thus, car B travels 300-100=200 miles.

It travels 5 hours, so car B speed is $\frac{200}{5}=40$ mph.

Since 50>40, car A traveled faster than car B.

The graph for the car A is steeper than the graph for the car B.

6 0

3 years ago

(a) Suppose one house from the city will be selected at random. Use the histogram to estimate the probability that the selected

vodka [1.7K]

Answer:

a. 0.71

b. 0.9863

Step-by-step explanation:

a. From the histogram, the relative frequency of houses with a value less than 500,000 is 0.34 and 0.37

-#The probability can therefore be calculated as:

$P(500000)=P(x=0)+P(x=500)\\\\\\\\=0.34+0.37\\\\\\\\=0.71$

Hence, the probability of the house value being less than 500,000 is o.71

b.

-From the info provided, we calculate the mean=403 and the standard deviation is 278 The probability that the mean value of a sample of n=40 is less than 500000 can be calculated as below:

$P(\bar X$

Hence, the probability that the mean value of 40 randomly selected houses is less than 500,000 is 0.9863

8 0

3 years ago

A scientist planted seeds in 4 sections of soil for an experiment. Not all of the

kakasveta [241]

Answer:

I think you would multiply 20 × 4 and the answer would be 80 that the scientist counted the number of plants in each 4 sections after 20 days.

4 0

3 years ago

Help me!! answer all

Sergio [31]

its blurry

Step-by-step explanation:

can you take a better picture

3 0

3 years ago

4(x−2+y) It's for khan academy