Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft
step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft
</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>
the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>
</span>
Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.
So if D is the diameter and h is the height of the conical pile then we can write:
D=3h
We know that diameter = 2r, where r is the radius
2r=3h
Volume of conical pile is given by formula
Given that volume is 1110 cubic feet.
Now plug the values of Volume and r into equation of volume
take cube root of both sides
7.78103342467=h
Hence height is approx 7.78 feet.
Let "radical 2" be represented by "r."
Then you are to simplify 4r + 7r - 3r. This comes out to 11r - 3r = 8r.
The answer is 8 radical 2.
B is the answer!
Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.
m is a common factor since you can take m out of both but it’s not the greatest common factor.
2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
3 because 2*12 24 24/8 is 3 hope this helps
