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Zarrin [17]
3 years ago
11

Juan buys 2.8 pounds of turkey. The turkey costs $4.55 for each pound. How much does Juan spend for the turkey?

Mathematics
2 answers:
Airida [17]3 years ago
8 0

Answer:

$12.74

Step-by-step explanation:

2(4.55)=9.10

.8(4.55)=3.64

9.10+3.64=

$12.74

nadya68 [22]3 years ago
4 0

Answer:12.75

Step-by-step explanation:

2.8X4.55

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Find the value of x to the nearest tenth.
nlexa [21]

Answer:

x = 14.7

Step-by-step explanation:

Using the sine rule

\frac{a}{sin(A)}  = \frac{b}{sin(B)}  = \frac{c}{sin(C)}

Substitute the given values.

\frac{7}{sin(20)}  = \frac{x}{sin(46)}

Rearrange the equation to get x on it's own.

\frac{7sin(46)}{sin(20)}  = x

x = 14.72246211

x = 14.7 (1dp)

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3 years ago
Three students, Matthew, Thompson and Amos shared #15000 in the ratio of 5:2:x respectively. If Matthew's share is 7500, calcula
jasenka [17]

Answer:

The value of x is 3.

Step-by-step explanation:

Matthew earned 7500 of 15000, which is exactly half the total amount, meaning that the fraction corresponding to his earnings is 1/2.

Rate of 5:2:x, with number 5 corresponding to Matthew, mean that his fraction of the earnings, in function of x is given by:

\frac{5}{5 + 2 + x} = \frac{5}{7 + x}

Both fractions are equal, so:

\frac{5}{7 + x} = \frac{1}{2}

Applying cross multiplication:

7 + x = 10

x = 10 - 7

x = 3

The value of x is 3.

5 0
3 years ago
A triangle has sides measuring 5 inches and 8 inches. If x represents the
lord [1]

Answer:

For me,the answer will be A.

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6 0
3 years ago
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3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

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3 years ago
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Answer:

x=2

Step-by-step explanation:

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