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Vikki [24]
3 years ago
6

4x+y=10 complete the missing value in the solution to the equation

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0

Answer: x+2 and y +2

Step-by-step explanation:

4x2+2=10

8+2=10

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The square of a number decreased by 3 times the number 28 find all possible values for the number
stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number  

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

a^2 - 3a = 28

a^2 - 3a - 28 = 0

Let us solve the above quadratic equation

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28

\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}

Thus the possible values of number are 7 and -4

5 0
3 years ago
Could you give me the answer of what is 1/4 of 268
MariettaO [177]
1/4 of 268 is basically 268/4 or 268 divided by 4

268 / 4 = 67

so 1/4 of 268 is 67
6 0
2 years ago
Read 2 more answers
Is 2.605 a rational number
gulaghasi [49]

Answer:

yes 2.605 is a rational number

6 0
2 years ago
Read 2 more answers
What is the difference between a linear equation and a quadratic equation?(in 7 sentences)
Kaylis [27]
A linear equation in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. It's possible to simplify this to y = mx + b, where m = ( −A / B) and b is the value of y when x = 0. A quadratic equation, on the other hand, involves one of the variables raised to the second power. It has the general form y = ax2 + bx + c. Apart from the adding complexity of solving a quadratic equation compared to a linear one, the two equations produce different types of graphs.
7 0
3 years ago
Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).
inna [77]

Answer:

\huge{ \fbox{ \sf{ \: ( \: 3 \: ,  \:  - 1 \: )}}}

Step-by-step explanation:

\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}

\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and  \: B(-2,-8) \: be \: (x2 \:, y2)}}

\underline{ \sf{Finding \: the \: midpoint}}

\boxed{ \rm{Midpoint \:  =  \: ( \frac{x1 + x2}{2}  \: ,  \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2}  \: ,  \:  \frac{6 + ( - 8)}{2} )}}

\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2}  \: ,  \:  \frac{6 - 8}{2} }})

\mapsto{ \sf{Midpoint = ( \frac{6}{2}  \: ,  \:  \frac{ - 2}{2}) }}

\mapsto{ \sf{Midpoint = (3 \: \:  ,   - 1)}}

Hope I helped!

Best wishes!! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
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