The answer is X=3 or x=5/3
Answer:
5(3√x) +9(3√x) = 15√x+27√x= 42√x
5∛x + 9∛x = 14∛x
Step-by-step explanation:
Answer:
(3, -6)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Terms/Coefficients
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 4x - 18
y = -5x + 9
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [2nd Equation]: 4x - 18 = -5x + 9
- [Addition Property of Equality] Add 5x on both sides: 9x - 18 = 9
- [Addition Property of Equality] Add 18 on both sides: 9x = 27
- [Division Property of Equality] Divide 9 on both sides: x = 3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x</em> [1st Equation]: y = 4(3) - 18
- Multiply: y = 12 - 18
- Subtract: y = -6
Answer:
Minimum = 10
Q1 (quartile 1) = 14.5
Medium = 16
Q3 (quartile 3) = 17
Maximum = 18
Step-by-step explanation:
You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.
Tell me if I'm correct please
Answer:
Step-by-step explanation:
Remark
The rate is going to be the same as the distance travelled in 1 hour. The units will be different.
Formula
d = r * t
Givens
d = 558 miles
t = 3 hours
Problem A
r = d / t
r = 558/ 3 = 186 miles / hr
Problem B
Givens
r = 186 miles / hour
t = 1 hour
d = ?
Solution
d = 186 mi/hr * 1 hr
d = 186 miles
<u>Note</u>
This looks really trivial, but it's not. You have to learn to see the difference between a number and its units. It's not very often that the numbers will be the same, but if the units differ, then it is an entirely different question.