A quadratic is an expression of the form ax²+bx+c.
If the quadratic is in the perfect square form, it could be factored to look something like this:
(x+a)² or (x-a)²
Both of the above forms have one solution, that is "-a" and "a" respectively.
So if your quadratic equation is of the form:
(x±a)² = b, where b > 0
You can solve for "x" by taking the square root of both sides and getting 2 solutions -- ±a±√b.
And if your quadratic equation is of the form:
(x±a)² = b, where b < 0
Then when you try taking the square root of both sides, you will have to take the square root of a negative number, which means you will not get a real solution. Therefore, there will be zero solutions.
And finally if your quadratic equation is of the form:
(x±a)² = b, where b = 0
Then you will have one solution -- ±a.
Hope that helps!
The value of Y is equal to 6.
ZERO
as it is eventually multiplied by 0
If the sol'ns are -9 and 9, then we can use this to form our eq'n:
(x - 9)(x + 9) = 0
x^2 - 81 = 0
so...
x^2 + z - 103 = x^2 -81
z - 103 = -81
z = -81 + 103
z = 22
The answer is C
Fell free to mark brainly if you want.
