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Troyanec [42]
3 years ago
15

Please help me:////.

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
The absolute value of a number is its distance from 0. An easy way to think about this is that the absolute value turns a negative number positive, and has no effect on positive numbers. In this case, we are taking the absolute value of a negative number. This means we should simply make the number positive. Therefore, the answer is \frac{1}{3}
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What is the slope. y=5/4 r-1
kirza4 [7]

Answer:

5

4

−

1

Step-by-step explanation:

8 0
3 years ago
In the diagram find the value of x
Alika [10]

Answer:

∠QRP=5x°

90°=5x°

x=18°

<h3><u>---------------------</u></h3><h3><u>hope it helps...</u></h3><h3><u>have a nice day!</u></h3>

7 0
3 years ago
Solve for kkk. \dfrac{k}4+ 3= 14 4 k ​ +3=14
masha68 [24]

Answer: k=1

Step-by-step explanation:

Simplify   1/k

    3     2         1

 (((—+2)-(—•k))-4)-(—-2)  = 0

    k     k         k

2.1   Subtracting a whole from a fraction

      2     2 • k

   2 =  —  =  —————

        1       k  

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

1 - (2 • k)     1 - 2k

———————————  =  ——————

     k            k  

Simplify  2/k

 3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

Simplify 3/k

  3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

5.1   Adding a whole to a fraction

 3                      (1 - 2k)

 (((— +  2) -  2) -  4) -  ————————  = 0

    k                         k    

6.1   Subtracting a whole from a fraction

        2     2 • k

   2 =  —  =  —————

        1       k  

7.1   Subtracting a whole from a fraction

3 + 2 • k     2k + 3

—————————  =  ——————

    k           k  

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

        2     2 • k

   2 =  —  =  —————

        1       k  

9.1     Pull out like factors :

  2 - 2k  =   -2 • (k - 1)

10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -2•(k-1)

 ———————— • k = 0 • k

    k    

Now, on the left hand side, the  k  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -2  •  (k-1)  = 0

Equations which are never true:

10.2      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

10.3      Solve  :    k-1 = 0

Add  1  to both sides of the equation :

                     k = 1

5 0
3 years ago
Find the equation of the exponential function represented by the table below:
UNO [17]

Answer:

Step-by-step explanation:

If this is an exponential function, it is of the form

y=a(b)^x  where x and y are coordinates from your table, a is the intial value, and b is the growth/decay rate.  To find out what the equation is that represents this data, choose 2 points and solve first for a and then for b.  Just a hint:  If at all possible, choose the coordinate that gives you an x of 0.  You'll see why in a minute.  

I chose the first 2 points from your table: (0, .2) and (1, .8).  Solving first for a:

.2=a(b)^0  The reason to choose the x of 0 as one of your points is because anything raised to the power of 0 is 1.  So our equation then becomes:

.2=a(1) so

a = .2   Easy enough.  

Now use that value along with the other coordinate to solve for b:

.8=.2(b)^1  b to the first is just b, so,

.8 = .2b

Divide both sides by .2 and you'll get that

b = 4

The equation, then, is

y=.2(4)^x which is growth, since the value for b is greater than 1.

5 0
3 years ago
Solve equation 5b - (5b -
tester [92]
Hello I believe your answer is going to be 2 I assumed the b's were x's

4 0
3 years ago
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