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3 years ago

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Please help me:////.

1 answer:

Hitman42 [59]3 years ago

5 0

The absolute value of a number is its distance from 0. An easy way to think about this is that the absolute value turns a negative number positive, and has no effect on positive numbers. In this case, we are taking the absolute value of a negative number. This means we should simply make the number positive. Therefore, the answer is $\frac{1}{3}$

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Terrence made a scale drawing of an American football field on a large piece of cardboard. An actual field is

iogann1982 [59]

Answer:

20

9

23

Step-by-step explanation:

4 0

3 years ago

In a chess tournament, each player plays every other player exactly once. If it is known that 105 games were played, how many pl

diamong [38]

Answer:

15 players played in the chess tournament.

Step-by-step explanation:

When there are 15 players, the first player plays 14 games and step aside.

remaining 14 player

next player plays 13 games. steps aside

remaining 13 players

next player plays 12 games. steps aside

remaining 12 players

next player plays 11 games. steps aside

remaining 11 players

.

.

.

.

Last player plays 1 game and steps aside

remaining 1 player who will not play against himself.

∴ Sum of all games played

= 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105 games played

3 0

3 years ago

Name the following segment or point.

frutty [35]

Answer:

should be segment BT, that's what i put and it was right. hope this helps

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

3 years ago

You are constructing deck chairs that require 12 2/3 feet of lumber each. How many feet of lumber will you use to make 15 chairs

Mrrafil [7]

As each chair needs 12.6667 feet lumber.So 15 chairs will need 15*12.6667=190.0005 lumber

5 0

3 years ago