Sadly, the answer to your question is 'No'. The work written under
the problem on the paper is not correct ... because you tried to do
too much !
You can't combine 'm' terms with 'n' terms or with plain numbers.
They all need to stay separate all the way to the end.
So, actually, your first written line is the answer . . . <em>7m - 35 + 3n</em>
That's as far as you can go. You can't combine these terms. Stop there !
Answer:
Enrollment at walnut junior = 142
Enrollment at walnut high = 710
Step-by-step explanation:
Let :
Enrollment at walnut junior = x
Enrollment at walnut high = 5x
Total enrollment in both schools = 852
Mathematically ;
x + 5x = 852
6x = 852
x = 142
5x = 142 * 5 = 710
Hence,
Enrollment at walnut junior = 142
Enrollment at walnut high = 710
4,248 times 0.90 equals 3823.2; so 3823.2 students are enrolled.
Answer:
1.86
Step-by-step explanation:
Given the following :
X : - - - - 0 - - - - 1 - - - - 2 - - - - - 3 - - - - 4
P(x) - 0.37 - - 0.28 - - 0.22 - - 0.22 - - 0.12
The mean of the distribution can be calculated by evaluated by determining the expected value of the distribution given that the data above is a discrete random variable. The mean value can be deduced multiplying each possible outcome by the probability of it's occurrence.
Summation of [P(x) * X] :
(0.37 * 0) + (0.28 * 1) + (0.22 * 2) + (0.22 * 3) + (0.12 * 4)
= 0 + 0.28 + 0.44 + 0.66 + 0.48
= 1.86