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Dominik [7]
3 years ago
10

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

unded to the nearest tenth.
A (−9, 3), B (−6, −1), C (2, 5), D (−5, 6)
Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

Perimeter = 5 + 5 + 7.1 + 10 =27.1

area = (5 + 10)x5  / 2 = 37.5

Step-by-step explanation:

Slope formula: m = (x' - x)/(y' - y)

m-AD: (6-3)/(-5 - -9) = 3/4    (I'm not detail other Other slopes)

m- BC = 3/4

m-AB = - 4/3

m-AD = m-BC         AD // BC      (ABCD is a Trapezoid)

m-AB = - 1 / m-BC

AB ⊥ BC

segment length formula: d = √(x' - x)² + (y' - y)²

AD = √(-5 - -9)² + (6 - 3)² = √4² + 3² = √25 = 5

DC = √50 = 7.1

BC = √100 = 10

AB = √25 = 5

Perimeter = 5 + 5 + 7.1 + 10 =27.1

area = (5 + 10)x5  / 2 = 37.5

area ABCD = (5+10)x5  / 2 =

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