The sides of the triangle are given as 1, x, and x².
The principle of triangle inequality requires that the sum of the lengths of any two sides should be equal to, or greater than the third side.
Consider 3 cases
Case (a): x < 1,
Then in decreasing size, the lengths are 1, x, and x².
We require that x² + x ≥ 1
Solve x² + x - 1 =
x = 0.5[-1 +/- √(1+4)] = 0.618 or -1.618.
Reject the negative length.
Therefore, the lengths are 0.382, 0.618 and 1.
Case (b): x = 1
This creates an equilateral triangle with equal sides
The sides are 1, 1 and 1.
Case (c): x>1
In increasing order, the lengths are 1, x, and x².
We require that x + 1 ≥ x²
Solve x² - x - 1 = 0
x = 0.5[1 +/- √(1+4)] = 1.6118 or -0.618
Reject the negative answr.
The lengths are 1, 1.618 and 2.618.
Answer:
The possible lengths of the sides are
(a) 0.382, 0.618 and 1
(b) 1, 1 and 1.
(c) 2.618, 1.618 and 1.
Its technically like 7/8 x 60 because 60 mins is an hour
36v - 12 = 12 .....add 12 to both sides
36v - 12 + 12 = 12 + 12...simplify
36v = 24...divide both sides by 36
(36/36)v = 24/36
v = 2/3 <===
10 of the numbers are even. 4 more are odd multiples of 3. The probability of landing on even or a multiple of 3 is (10+4)/21 = 2/3.
With questions like this (to see if theyre parallel), all you have to do is see if lines have a congruent slope. if yes (ex: 2 and 2), then they are parallel. if the slopes are opposites (ex: 4 and -1/4), then they are perpendicular. If they have no such relation (ex: -3 and 1/7), then they are neither.
with this problem, find the slope by separating the same variable in each equations, like this:
2x + 7y = 6
-2x -2x
7y = -2x + 6
(the second equation is already separated) so now we have
7y = -2x + 6 and 7y = 2x + 6
since -2 does NOT equal 2, these two graphs/lines are NOT parallel.
Hope this helped!
