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Nataliya [291]
4 years ago
7

A 28-year-old man pays $181 for a one-year life insurance policy with coverage of $150,000. If the probability that he will live

through the year is 0.9994, what is the expected value for the insurance policy?
Mathematics
1 answer:
Marina CMI [18]4 years ago
3 0
Expected value E(x) = 0.9994(150000 - 181) = 0.9994 x 149819 = $149,729.11
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Firemen are using a 60-foot ladder to reach
Katarina [22]

Answer:

  1. This might help a liitle its kind of like the question you are asking.
  2. You might not want to give people 5 points for a long question because most of them might not awnser.

Step-by-step explanation:

Download pdf
5 0
3 years ago
How many times greater is the 4 in the thousands place compared to the 4 in the hundreds place?
lora16 [44]
It is 10 more in the thousands than the hundreds... multiply 100 x 10...
4 0
3 years ago
I need help with this, please. Any advice would be appreciated.
mote1985 [20]

Answer:

see explanation

Step-by-step explanation:

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

where a₁ is the initial value and d the common difference

Given

S_{n} = \frac{n}{2} [ 10 + (n - 1)3 ]

Then by comparison

2a₁ = 10 ( divide both sides by 2 )

a₁ = 4 ← initial value

and d = 3 ← common difference

Thus

S_{8} = \frac{8}{2} [ 10 + (7 × 3) ]

   = 4(10 + 21)

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8 0
4 years ago
10 points!! Pls help with 5 and 6
marissa [1.9K]

Answer:

I only know number 5 so here it is

the solution for the left is: 2x6=12

the solution for the right is: 5x3+4x1=15+4=19

and the answers are: 1.12 . 2.19

5 0
3 years ago
It is known that 60% of customers will need additional maintenance on their vehicle when coming in for an oil change. A random s
inn [45]

Answer:

the probability that more than 70% of customers in the sample will need additional maintenance is 0.0371

Step-by-step explanation:

From the information given:

we are to determine the probability that more than 70% of customers in the sample will need additional maintenance

In order to achieve that, let X be the random variable that follows a binomial distribution.

Then X \sim Bin(48, 0.6)

However 70% of 48 samples is

= 0.7 × 48 = 33.6 \simeq 34

Therefore, the required probability is:

= P(X> 34)

= \sum \limits ^{48}_{x=34} (^{48}_{x}) (0.6)^x(1 - 0.6)^{48-x}

= \dfrac{48!}{34!(48-34)!} (0.6)^{34} (0.4)^{48-34}

= 4.823206232 \times 10^{11} (0.60)^{34}(0.4)^{14}

= 0.03709524328

\simeq 0.0371

3 0
3 years ago
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