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3 years ago

What is the percent decrease from 120% to 90%

Mathematics

1 answer:

boyakko [2]3 years ago

7 0

30% decrease.

120-90 = 30

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1/1-cosA-1/1+cosA=2cotAxcosecA

castortr0y [4]

Answer:

just apply the formulas then see dummy

5 0

2 years ago

4(2x - 7) - 2x = -10

jarptica [38.1K]

So the right answer is 3.

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3 years ago

Read 2 more answers

Find the x-intercepts, y-intercepts, and the vertex of the following equation. y=x2 – 2x – 15

sineoko [7]

X intercept : (5,0),(-3,0)
y intercept : (0,-15)
vertex: (1,-16)

i’m glad to help! mark me brainliest if i’m correct plss

6 0

3 years ago

Find the x- and y- intercepts of parabola y=5x^2-16x+10

____ [38]

Y-INTERCEPT

$y = 5x^2 - 16x + 10$

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

$\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10$

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

$y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0$

We need to use the quadratic formula

The quadratic formula helps us find what values of $x$ make the equation = 0

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\$

The x-intercepts are at:

$(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)$

5 0

2 years ago

Find the slope of the line passing through the given points (7, 13) and (2, -12).

tatyana61 [14]

Answer:

The answer is C.

Step-by-step explanation:

m=y²-y¹/x²-x¹

m=(-12)-13/2-7

m=-25/-5

m=5

4 0

3 years ago