Answer:
Step-by-step explanation:
Total number of red disk=6
Total number of yellow disk=2
Total disk=6+2=8
Odd number=1,3,5,7=4
Odd number on red disk=1,3,5=3
Probability,
Using the formula
The probability of getting odd number disk=
The probability of getting odd numbered red disk=
The probability of selecting a red disk,given that an odd numbered disk is selected=
Using conditional probability
Answer:
Jane's age = X
In 2 years time = X + 2
In 5 years time = X + 5
Step-by-step explanation:
Answer from Gauth math
The correct answer is 3: 35
Explanation:
To calculate at what time Jenny will arrive in Rochefort, the first step is to calculate the approximate time of the trip. Now, to calculate this consider the time of a movement (t) equals to the distance (d) divided by the speed (s), the process is shown below:
t = 483 km / 84 km/h
t = 5.75 hours
In this number 5 refers to the hours and 0.75 represents 45 minutes considering 0.75 x 60 minutes in one hour = 45 minutes. Therefore, the total time from Paris to Rochefort is 5 hours and 45 minutes. Now, to calculate the time of arrival add this result to the time of departure.
Add the hours: 5 hours + 9 hours: 14 hours
Add the minutes: 50 minutes + 45 minutes =95 minutes
95 minutes are equivalent to 1 hour (60) minutes and 35 minutes
Calculate the total
Hours: 14 hours + 1 hour = 15 hours or 3 in the 12 hour system (15 hours - 12 hours = 3 p.m.)
Minutes: 35 minutes
Answer:
Mean and IQR
Step-by-step explanation:
The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.
For company A:
Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.
Hence, the mean will be the best measure of centre rather Than the median in this case.
For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.
Answer: 3.5 + 4t ≤ 39.5
Step-by-step explanation: To represent this situation we wrote an inequality.
