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zubka84 [21]
3 years ago
5

the volume of jupiter is about 1.43×10^15 cubic kilometers. The volume of Earth is about 1.09×10^12 kilometers. The number of ea

rths that can fit inside jupiter can be found by dividing jupiters volume by earths volume
Mathematics
2 answers:
Butoxors [25]3 years ago
7 0

divide the volume of jupiter by the volume of earth

1.43*10^15/ 1.09*10^12

1.43/ 1.06 *10^(15-12)  divide the number, subtract the exponent

1.311926606 *10^3


torisob [31]3 years ago
4 0

Answer:

1312

Step-by-step explanation:

1.43 * 10^15 / 1.09 * 10^12

=  1.312 * 10^3

or about   1312 earths


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koban [17]

Answer:

\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}

Step-by-step explanation:

\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228

=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}

\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}

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3 years ago
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Answer:

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Step-by-step explanation:

Remember that slope intercept form is Y = mx + b indicating that m is the slope

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So the answer is y = 50x

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2 years ago
What is the slope of this line?​
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Step-by-step explanation:

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krek1111 [17]

Answer:

The shortest length of wire that can be used is 29.47 ft.

Step-by-step explanation:

To solve this problem we can follow the following steps:

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2) Since the speaker is on the ceiling, and the amplifier is on the floor, then 7 more feet of wire is needed to reach the speaker. <em>Observe the attached image</em>

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d = 22.47\ ft + 7\ ft\\\\d = 29.47\ ft

6 0
3 years ago
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