Answer:
Following are the program in python language
def prob3_6(k): #function definition
c = 0 #variable declaration
while k != 1: #iterating the while loop
print(k) #print k
if k % 2 == 0:#check if condition
k= k // 2 #divisible by 2
else: #else condition
k = k * 3 + 1
c = c + 1
print(k) #print k
print c #print count
prob3_6(3)#function call
Output:
3
10
5
16
8
4
2
1
7
Explanation:
Following are the description of program
- Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
- Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
- After that we iterated the while for print the value of when it is not equal to 1 .
- We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
- Finally print "k" and "c"
Explanation:
save as because if u want to save the bame of it press save as to save it as what u want
Answer:
This is because the key in relationships['jimmy'] is wrong. The first letter "j" should be uppercase. The key in the given dictionary is "Jimmy" and therefore a lowercase "j" will result in a KeyError exception. The key is case sensitive and therefore a minor mistake in a single letter either in lowercase or uppercase will cause the error. The correct usage of key to address the value should be relationships["Jimmy"].
I believe the answer is font.
