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user100 [1]
3 years ago
15

What is the probability of the complement of rolling a number less than 5 by using a six-sided die?

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
<h3><u>Answer:</u></h3>

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

<h3><u>Step-by-step explanation:</u></h3>

Let A denote the event of rolling a number less than 5 in a six-sided die.

Now, we know that the Total outcomes are: 6

since, the sample space is given as: {1,2,3,4,5,6}

Also Number of favorable outcomes are: 4

since the numbers which are less than 5 are {1,2,3,4}

Now we have to find:

P(A^c)

where P denotes the probability of an event and A^c denote the complement of event A.

We know that:

P(A^c)=1-P(A)

Now,

P(A)=\dfrac{4}{6}\\\\P(A)=\dfrac{2}{3}

Hence,

P(A^c)=1-\dfrac{2}{3}\\\\P(A^c)=\dfrac{3-2}{3}\\\\P(A^c)=\dfrac{1}{3}

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

PSYCHO15rus [73]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

i did it

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After paying 8 dollars for the pie, Keith has 68 dollars left, his friend
slavikrds [6]

Answer:

75$ BEFORE buying pie. friend doesn't matter

Step-by-step explanation:

68+7 = 75

5 0
2 years ago
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I don’t know what to do on here it’s really hard and I need help for the answer
Alla [95]
Ok so our original fraction is:
\frac{36 {x}^{12} }{6 {x}^{9} }
To simplify this fraction, look for instances where the values on the top and bottom can be reduced:

For example, 36 over 6 is the same as 6 over 1, so we can simplify the fraction so it is:
\frac{6 {x}^{12} }{ {x}^{9} }
We can also eliminate the denominator by dividing the nominator by x^9 so:
\frac{6 {x}^{12} }{ {x}^{9} }  \div  \frac{ {x}^{9} }{ {x}^{9} }
= 6 {x}^{3}
And that is the simplified answer of the fraction

Hope this helped
5 0
2 years ago
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
Function g is a transformation of function f.
bulgar [2K]

The equation of function g(x) in terms of f(x) is g(x) = -3[f(x)].

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given:

genera form of an exponential function is  y=aeᵇˣ

Now, equation for f(x) is

f(x) = e^{(log \;2)x} -2

Similarly, graph for g(x) is

g(x) = -3e^{(log \;2)x} +6

Comparing the two function a relation can  be establish

g(x) = -3[f(x)]

Learn more about Equation here:

brainly.com/question/2263981

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Answer:

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2 years ago
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