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user100 [1]
3 years ago
15

What is the probability of the complement of rolling a number less than 5 by using a six-sided die?

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
<h3><u>Answer:</u></h3>

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

<h3><u>Step-by-step explanation:</u></h3>

Let A denote the event of rolling a number less than 5 in a six-sided die.

Now, we know that the Total outcomes are: 6

since, the sample space is given as: {1,2,3,4,5,6}

Also Number of favorable outcomes are: 4

since the numbers which are less than 5 are {1,2,3,4}

Now we have to find:

P(A^c)

where P denotes the probability of an event and A^c denote the complement of event A.

We know that:

P(A^c)=1-P(A)

Now,

P(A)=\dfrac{4}{6}\\\\P(A)=\dfrac{2}{3}

Hence,

P(A^c)=1-\dfrac{2}{3}\\\\P(A^c)=\dfrac{3-2}{3}\\\\P(A^c)=\dfrac{1}{3}

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

PSYCHO15rus [73]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

i did it

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That are the greatest common factors of 16 28 and 48
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4

Step-by-step explanation:

The factors of 16 are:1 2 4 8 16

the factors of 28 are:1 2 4 7 14 28

the factors of 48 are: 1 2 3 4 6 8 12 16 24 48

and so the common factors are :1 2 4 the greatest one is 4 and so the answer is 4

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A simple random sample of 12 iPhone's being sold over the Internet had the
bearhunter [10]

Answer:

The upper bound is 399.5

Step-by-step explanation:

Let's start by calculating the mean value of the distribution as the addition of all values given divided by 12:

Average = 289.75.

If the standard deviation is 56, then the upper bound in 95% the confidence interval for the mean price of the phones is going to be given by the mean value added to 56 times 1.96 (since 95% of the population is withing 1.96 times the standard deviation)

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7 0
3 years ago
Plz answer my question it is urgent..!!
oee [108]

Answer:

In the step-by-step explanation!

Step-by-step explanation:

Not sure if it is too late but here:

1.)

\frac{1}{\alpha}+\frac{1}{\beta} \\\frac{\beta}{\alpha \beta } +\frac{\alpha}{\alpha \beta } \\\frac{\alpha +\beta }{\alpha \beta }

2.)

\frac{1 }{\alpha } *\frac{1}{\beta} = \frac{1*1}{\alpha*\beta} =\frac{1}{\alpha \beta}

3.)

\frac{1}{\alpha}-\frac{1}{\beta}\\ \frac{\beta}{\alpha \beta } -\frac{\alpha }{\alpha \beta } \\\frac{\beta -\alpha }{\alpha \beta }

Hopes this help! Please give me Brainliest!

6 0
3 years ago
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