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mrs_skeptik [129]

2 years ago

9

Find the equation of a line, in slope intercept form of a line that passes through the point (9,2) and is perpendicular to the l

ine 2x-y=8

1 answer:

son4ous [18]2 years ago

7 0

Answer:

the first one is correct ive T a k e n this testing.

Step-by-step explanation:

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Volume questionnnnnn

qaws [65]

Answer:

a

Step-by-step explanation:

5 0

1 year ago

The perimeter of a circle is 132 cm calculate its radius and area

son4ous [18]

Answer:

r≈21.01cm

Step-by-step explanation:

I think that's the exact answer

4 0

2 years ago

Solve with completing the square method:<br>6x²-7x+2=0 and ax²+bx+c=0

Norma-Jean [14]

$6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^{2}-4ac = (-7)^{2}-4*6*2=49-48=1 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{7-\sqrt{1}}{2*6}=\frac{7-1}{12} =\frac{6}{12}= \frac{1}{ 2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{7+\sqrt{1}}{2*6}=\frac{7+1}{12} =\frac{8}{12}= \frac{2}{ 3}$

7 0

2 years ago

A survey found that women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also

Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that women's heights are normally distributed.

Population mean : $\mu =63.2 \text{ inches}$

Standard deviation: $\sigma= 2.4\text{ inches}$

Minimum height = 4ft. 9 in.= $4\times12+9\text{ in.}=57\text{ in.}$

Maximum height = 6ft. 2 in.= $6\times12+2\text{ in.}=74\text{ in.}$

Let x be the random variable that represent the women's height.

z-score : $z=\dfrac{x-\mu}{\sigma}$

For x=57, we have

$z=\dfrac{57-63.2}{2.4}\approx-2.58$

For x=74, we have

$z=\dfrac{74-63.2}{2.4}\approx4.5$

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

$P(-2.58$

Hence, the percentage of women meeting the height requirement = 99.51%

8 0

2 years ago

Question: Help plsss

Mice21 [21]

Answer:

I hope it help............

3 0

1 year ago