All categories

2 years ago

What number added to 66 is 167

Mathematics

1 answer:

denis-greek [22]2 years ago

5 0

Answer:

101

Step-by-step explanation:

To figure this out, you would do 167 - 66 = 101

101 + 66 = 167

You might be interested in

If f(x)= 5x + 4 and g(x) = 1/2x<br><br> find ,<br> a) fg(5)

Veseljchak [2.6K]

Answer:

f(g(5)) = 16.5

Step-by-step explanation:

To calculate f(g(5)), evaluate g(5) then substitute the value obtained into f(x)

g(5) = $\frac{1}{2}$ × 5 = 2.5 , then

f(2.5) = 5(2.5) + 4 = 12.5 + 4 = 16.5

5 0

2 years ago

Read 2 more answers

Does the graph represent a function ? Why or Why not ?

Bogdan [553]

Answer:yes

Step-by-step explanation: the answer does represent a function because if you were to put points in the line wherever, and connect them by drawing a line vertically, it would not cross two points.

3 0

3 years ago

Select the correct answer. Factor the polynomial below. 4x^2-16 A. 4(2 - x)2 B. 4(2 + x)(2 - x) C. 4(x - 2)2 D. 4(x + 2)(x - 2)

Stells [14]

Answer:

The answer is D

4(x²-4)=4(x-2)(x+2)

6 0

1 year ago

Chen is growing vegetable plants. His bean plant is 6 centimeters tall. His tomato plant is 5 times as tall as his bean plant. w

Alinara [238K]

Answer:

6*5=30cm (Height of tomato plant)

Step-by-step explanation:

bean plant is 6 centimeters tall

tomato plant is 5 times as tall as his bean plant

6*5=30cm

6 0

3 years ago

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

kupik [55]

Answer:

(a) 0.873 (b) 0.007 (c) 0.715 (d) 0.277 (e) 1.25 and 1.09

Step-by-step explanation:

The probability that the random variable X takes the value x is given by P(X=x) = $25Cx 0.05^x0.95^{25-x}$ . Then,

(a) $P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})= 0.873$

(b) $P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007$

(c) $P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715$

(d) $P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277$

(e) E(X) = np = (25)(0.05) = 1.25 and $Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09$

8 0

2 years ago