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astra-53 [7]
3 years ago
9

What number added to 66 is 167

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer:

101

Step-by-step explanation:

To figure this out, you would do 167 - 66 = 101

101 + 66 = 167

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2x - (-8) - 7x + 4 +10
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The phenomenon of bottle flipping has hit the nation. You design a machine that can randomly flip a bottle. You observe 2180 ran
krek1111 [17]

Answer:

The variable of interest is the proportion of flips that land the correct way when flipped randomly.

The necessary conditions n\pi \geq 10 and n(1-\pi) \geq 10 are present.

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

Step-by-step explanation:

Variable of Interest:

Proportion of flips that land the correct way when flipped randomly.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Necessary conditions:

The necessary conditions are:

n\pi \geq 10

n(1-\pi) \geq 10

You observe 2180 random, independent flips, and 325 land the correct way.

This means that n = 2180, \pi = \frac{325}{2180} = 0.149

Necessary conditions

n\pi = 2180*0.149 = 325 \geq 10

n(1-\pi) = 2180*0.851 = 1855 \geq 10

The necessary conditions n\pi \geq 10 and n(1-\pi) \geq 10 are present.

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.33.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.131

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 + 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.167

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

8 0
3 years ago
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