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VladimirAG [237]
3 years ago
6

Lines AB and CD (if present in the picture) are straight lines. Find x. Give reasons to justify your solutions.

Mathematics
1 answer:
MrRa [10]3 years ago
3 0

Answer:

180- 110= 70

70+x+90=180

160+x=180

180-160=x

20=x

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Which choice is equivalent to the quotient shown here when x > 0
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Step-by-step explanation:

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3 years ago
Find the median of the set of data. 30, 16, 49, 25 <br><br>​
weeeeeb [17]

Answer:

16,25,30,49

25+30=55

55÷2=27.5

Step-by-step explanation:

median means the middle value of any set of data so first arrange the data into ascending order.

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the data is even so we take both the middle value , add it and divide it with 2

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4 0
3 years ago
The sum of 4 consecutive numbers is equal to the sum of the next 3 consecutive numbers. Find the largest number.​
timurjin [86]

Answer:

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Step-by-step explanation:

Let n = the number

n + (n + 1) + (n + 2) + (n + 3) = (n + 4) + (n + 5) + (n + 6)

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Proof:

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Hope this helps! Have an Awesome Day!!  :-)

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y=(x-6)^2+2 Have a nice day

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We did not find results for: A measure of​ malnutrition, called the​ pelidisi, varies directly as the cube root of a​ person's w
asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\&#10;\begin{array}{llll}&#10;\textit{\underline{y} varies directly with \underline{x}}\\&#10;\textit{and inversely with \underline{z}}&#10;\end{array}\implies y=\cfrac{kx}{z}\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\

\bf \begin{cases}&#10;p=pedalisi\\&#10;w=weight\\&#10;s=\textit{sitting height}&#10;\end{cases}\quad &#10;\begin{array}{llll}&#10;%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.&#10;\textit{pelidisi varies directly}\\&#10;\textit{as cube root of weight}\\&#10;\textit{and inversely to }\\&#10;\textit{sitting height}&#10;\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\&#10;-------------------------------

\bf \textit{we know that }&#10;\begin{cases}&#10;w=48,820\\&#10;s=78.7\\&#10;p=100&#10;\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}&#10;\\\\\\&#10;100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k&#10;\\\\\\&#10;thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}&#10;\\\\\\&#10;\textit{now, what is \underline{p} when }&#10;\begin{cases}&#10;w=54,688\\&#10;s=72.6&#10;\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
3 0
4 years ago
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