Question

What is the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) ?

Answer 1

Answer: $(y-5)=\dfrac{-6}{-11}(x-7)$

Step-by-step explanation:

We know that the point slope form of a line that passes through two points (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Similar;y , the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) will be :-

$(y-5)=\dfrac{-1-5}{-4-7}(x-7)$

$(y-5)=\dfrac{-6}{-11}(x-7)$

Hence, the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) is given by :-

$(y-5)=\dfrac{-6}{-11}(x-7)$

Answer 2

As the equation of the line with two points (a,b) and (c,d) is given by

(x-a)/(c-a) = (y-b)/(d-b)

We have

(x-7)/(-4-7) = (y-5)/(-1-5)

(x-7)/(-11) = (y-5)/(-6)

6(x-7) = 11(y-5)

6x-42=11y -55

11y= 6x-42+55

11y = 6x+13

y=(6/11)x + (13/11) is the respective slope intercept form of it