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kari74 [83]
3 years ago
11

A car repair shop charged $80 per hour for labor and $210 for the parts of a car. If the total cost of repair for the car was $4

90, how many hours did it take to repair the car?
Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Hello!

\bf Answer:

It took \boxed{ \bf 3.5} hours to repair the car.


\bf Explanation:

First, subtract the cost of car parts from the total amount spent:

490 - 210 = 280

Divide this by cost of labor per hour:

280 ÷ 80 = 3.5

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7) Original price: ?<br> Discount: 25%<br> Sale price:<br> $28
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Answer:

Step-by-step explanation:

let be x the price before the discount

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25h to the power of 10 +18
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Answer:

1.509909034 x10 ^36

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Image attachment below, Algebra 1 stuff
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I know you didn't want an explanation, but I'll give you one anyway.
So, for a function, when you have f(5) = , then you'll put that 5 in for all of the x's in the function. 

The first batch of problems gave you the equation f(x) = \frac{x}{2} + 3. Now, plug in the numbers given for s and solve.

1. f(5) = <span>\frac{x}{2} + 3   Plug in 5 for x
</span>         = \frac{5}{2} + 3   Make three into a fraction over 2
         = \frac{5}{2} + <span>\frac{6}{2}   Add
         = </span><span><span>\frac{11}{2}

</span>2. f(-4) = </span><span>\frac{x}{2} + 3   Plug in -4 for x
           = </span><span>\frac{-4}{2} + 3   Divide -4 by 2
           = -2 + 3   Add
           = 1

For the next set, you have g(x) = x</span>² + 1.

3. Let's split this up. Solve the first equation, then the second, and then put         the answers together to solve it.

g(4) = x² + 1   Plug in 4 for x
       = 4² + 1   Square
       = 16 + 1   Add
       = 17

g(3) = x² + 1   Plug in 3 for x
       = 3² + 1   Square
       = 9 + 1   Add
       = 10

Now, put the two together.

g(4) + g(3) =    Substitute in the answers you just got.
      17 + 10 =    Add
                  = 27         

4. g(-1) = x² + 1      Substitute in -1 for x
            = (-1)² + 1   Square
            = 1 + 1        Add
            = 2

5. g(-6) = x² + 1       Plug in -6 for x
             = (-6)² + 1   Square
             = 36 + 1      Add
             = 37

For the last set, we have h(x) = x² + 7 and k(x) = 4x - 5. We'll have to pay close attention to the starting variables here.

6. h(-6) = x² + 7       Plug in -6 for x
             = (-6)² + 7   Square
             = 36 + 7      Add
             = 43

k(4) = 4x - 5     Plug in 4 for x
       = 4(4) - 5   Multiply
       = 16 - 5      Subtract
       = 11

Put the two answers into the final equation.

h(-6) + k(4) =    Substitute in the answers you got
       43 + 11 =    Add
                   = 54

7. k(10) = 4x - 5       Plug in 10 for x
            = 4(10) - 5   Multiply
            = 40 - 5      Subtract
            = 35

h(2) = x² + 7   Plug in 2 for x
       = 2² + 7   Square
       = 4 + 7     Add
       = 11

Now, put those into the equation.

k(10) - h(2) =    Plug in the answers you got
       35 - 11 =    Subtract
                  = 24

8. For this one, it wants you to add h(x) and k(x). We don't need to plug anything into the equations this time because they're both already solved for x! So, you can just set this up like a standard find-x equation.

(x² + 7) + (4x - 5) =
    x² + 7 + 4x - 5 =   Combine like terms (7 and -5)
         x² + 2 + 4x =    Reorder so the variables come first
                            = x² + 4x + 2

  
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