Answer:
22,500 feet
Step-by-step explanation:
Initial Height of the airplane = 35000 feet
Rate of descend = 2500 ft/min
This means for every minute the height of the plane is decreasing by 2500 feet.
We have to find how high above the sea level is the airplane after 5 minutes.
Since, in one minute the distance of plane is decreasing by 2500 feet, in 5 minutes the decrease in its distance would be = 2500 x 5 = 12,500 feet
Thus, after 5 minutes the height of airplane would have decreased by 12,500 feet. Since, the initial height of airplane was 35,000 feet, the new height after 5 minutes would be:
Height after 5 minutes = 35000 - 125000 = 22,500 feet
After 5 minutes, airplane is 22,500 feet above the sea level
Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.
If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

So, at the moment, our parallel line looks like this...
y=(2/3)*x + C
However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.
-2=(2/3)*(1) + C
Therefore:
C = - 2 - (2/3)
C = - 6/3 - 2/3
C = - 8/3
This means that the line you are looking for is:
y=(2/3)*x - (8/3)
Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.
Answer:
(x - 4)(x^2 + 7)
Step-by-step explanation:
x^2 is a factor of the first two terms: x^3 - 4x^2 = x^2(x - 4).
7 is a factor of the last two terms: 7(x - 4).
Note how (x - 4) is a factor of the entire four-term expression given above.
Then: x^3-4x^2+7x-28 = (x - 4)(x^2 + 7)
210, 420, 630, 840
multiples of 2*3*5*7
Greetings!Simplify the Expression.
Distribute the Parenthesis.
How? Multiply the terms inside the Parenthesis by the term outside of the Parenthesis.
Combine Like Terms.

![\left[\begin{array}{ccc}8x^2-12x\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8x%5E2-12x%5Cend%7Barray%7D%5Cright%5D%20)
Hope this helps.
-Benjamin