a) 3(-2) + 4(3) = -6 + 12 = 6
b) 2(-2) -3(3) +5 = -4 -9 + 5 = -8
c) 4(-2) -(3) = -8 -3 = -11
d) -(-2) -2(3) = 4 -6 = -2
e) (1/2)(-2) +(3) = -1 +3 = 2
f) (2/3)(3) -(1/2)(-2) = 2 + 1 = 3
A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate. An equation that produces such a set of ordered pairs defines a function. What is the catch? There can be at most one output for every input.
Answer:
I need more context, can you take a screenshot of the actual question or something.
Step-by-step explanation:
Normally, you would do whatever is inside of the parenthesees first then do the rest but we cant get any further so we remove the parenthasees by distrubtion
7a+6b-4(3a-3b)
-4(3a-3b)
a(b+c)=(ab)+(ac)
-4(3a-3b)=-12a-(-12b)
7a+6b-12a+12b
7a-12a+6b+12b
-5a+18b
that's the asnwer