Hi there!
We can evaluate using the power rule and trig rules:
Therefore:
![\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B12%7D_%7B2%7D%20%7Bx-sin%28x%29%7D%20%5C%2C%20dx%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7Dx%5E%7B2%7D%2Bcos%28x%29%5D_%7B2%7D%5E%7B12%7D)
Evaluate:
Answer:
3
Step-by-step explanation:
3 plates per stack
divide 4 by 4 to get one and 12 by 4 to get 3
The function, g(x), has a constant rate of change and will increase at a faster rate than the function f(x) for all the values of x.
Given:
g(x) = 5/2 x -3 ..... (1)
f(x) = - 3.5 at x = 0
So, putting the value of x=0 in equation (1) for comparison. We get,
g(x) at x = 0
=> g(x) = 5/2 x (0) - 3
=> g(x) = -3
In this value of x function g(x) is faster than function f(x) having a value equal to -3.5.
Similarly, put x = 1 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (1) - 3
=> g(x) = (5-6)/2
=> g(x) = -1/2
In this value of x function g(x) is faster than function f(x) having a value equal to -1.
Similarly, put x = 2 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (2) - 3
=> g(x) = (5-3)
=> g(x) = 2
In this value of x function g(x) is faster than function f(x) having a value equal to 1.5.
Similarly, put x = 3 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (3) - 3
=> g(x) = (15/2 - 3)
=> g(x) = 7.5 - 3
=> g(x) = 4.5
In this value of x function g(x) is faster than function f(x) having a value equal to 4.
Therefore, for all values of x function g(x) is faster than function f(x).
function f(x).
To learn more about the function visit: brainly.com/question/14996787
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Answer:
-0.8333
Step-by-step explanation:
used omni calculator
https://www.omnicalculator.com/math/slope
Answer:
-6.95 x 10^10
Step-by-step explanation:
