The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
x = 
Step-by-step explanation:
4x-y+2z = 8x+y-4
4x-8x-y+2z = 8x - 8x +y-4
-4x -y +2z= y-4
-4x -y+y +2z = y+y-4
-4x +2z = 2y-4
-4x+2z-2z = 2y-2z-4
-4x = 2y-2z-4
=
Answer:
1. B
2. Seven Hundred thousand nine hundred and four
Step-by-step explanation:
5(3x-1)
(x-3)(x-2)
I don't know if you want working out or an explanation? Or if it's too late, sorry.
