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adoni [48]
3 years ago
6

How do u do this it's something about solving proportions and I have no idea how to do this plz help

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0
Simple...what fun!

To solve for this type of problem...it's real simple!

I will show you the easiest and fastest way to solve...

so..you have...

\frac{2}{5} = \frac{x}{35}

Just..CROSS MULTIPLY!!

2*35=70
and
5*x=5x

Leaving you with....

5x=70

Easy...now divide!!

\frac{5x}{5} = \frac{70}{5}

x=14

To check your work...plug it in....

\frac{2}{5} = \frac{14}{35}

simplify...

14/7=2

and

35/7=5

Thus, your answer.


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Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
34 divided by 3 3/4 equals what in fraction form
anygoal [31]

Answer:

9.06

Step-by-step explanation:

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Solve the problem.
ELEN [110]
Um, I never learn this, sorry but I’m in online class
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Valentin [98]
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