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jeyben [28]
3 years ago
6

PLS I NEE HELP! :( Factor 15x^2y^2−3x^3y+75x^4 . Show your work.

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer:

3x^2 (5y^2 - xy + 25x^2)

Step-by-step explanation:

Debora [2.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

3x^2(5y^2 -xy + 25x^2) is the factor

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How many half-lives of radon-222 have passed in 11.46 days? If 5.2 × 10−8 g of radon-222 remain in a sealed box after 11.46 days
Svetach [21]

Answer:

(i) Approximately 3 half lifes

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Step-by-step explanation:

(i) ∵ The half life of Radon-222 is approximately 3.8 days,

So, the number of half life in 11.46 days = \frac{11.46}{3.8} ≈ 3

(ii) Since, the half life formula is,

N=N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

Where,

N_0 = initial quantity,

t = number of periods

t_{\frac{1}{2}} = half life of the quantity,

Given,

N = 5.2\times 10^{-8}\text{ g}

t = 11.46 days,

t_{\frac{1}{2}} = 3.8\text{ days}

\implies 5.2\times 10^{-8}=N_0 (\frac{1}{2})^\frac{11.46}{3.8}

\implies N_0=2^{\frac{11.46}{3.8}}\times 5.2\times 10^{-8}\approx 4.21\times 10^{-7}\text{ g}

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