<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
Look at each term. How does the next one change? what is added?
The answer is 6, because there is an increase of 6 for each term
Answer:
x=7, so the smaller number is 7 and the larger number is 21.
Step-by-step explanation:
x=3x+5=33
Let x=3:
(3)+3(3)+5=3+9+5=17, not 33, so x is not 3
Let x=5:
(5)+3(5)+5=5+15+5=25, not 33, so x is not 5
Let x=7:
(7)+3(7)+5=7+21+5=33, so x=7
Let x=9:
(9)+3(9)+5=9+27+5=41, not 33, so x is not 9
Therefore x=7. Because x represents the smaller number, and the larger number is 3 times the smaller number, the smaller number is 7 and the larger number is 3(7)=21.
Yes, this is correct. The tenths place is the first number to the right of the decimal. There is a 3 in that spot
To find if it rounds up or down, follow this rule.
Less than 5 round down and greater than 5 round up.
For this you look to the number next to it which is 7.
It rounds up so it is 9.4
