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3 years ago

In an expression(8/9) squared (-81)+3/5dividedby-9/10

2 answers:

6 0

If you wanted to calculate it, there it is:
$(\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}$

aliya0001 [1]3 years ago

4 0

Answer: -64.0066666667

(((8\9)squared)*(-81))+(((3\5)\(-9))\10)

Step-by-step explanation:

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F(x)=18x+11, find f(5)

Natalija [7]

Answer:

$\boxed {\tt f(5)=101}$

Step-by-step explanation:

We are given the function:

$f(x)=18x+11$

and asked to find f(5). Therefore, we must substitute 5 in for each $x$ .

$f(5)=18(5)+11$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Multiply 18 and 5.

$f(5)=90+11$

Add 90 and 11.

$f(5)=101$

f(5) is equal to 101.

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3 years ago

A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con

Mashutka [201]

The tank with Chemical X "takes up" a space of 25ft³. Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume. The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5V
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
$\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V$
To find the volume of a cylinder, we find the base area and multiply by the height. We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
$16 \frac{2}{3}=3.2h \\ 16 \frac{2}{3}=3 \frac {2}{10}h$
We would now divide both sides by 3 2/10:
$\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}$
This is the same as:
$\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}$
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.

8 0

2 years ago

What is the y-intercept of a line perpendicular to y= 1/2x + 6 that passes through the point (4,-3)

Finger [1]

Answer:

(0,5)

Step-by-step explanation:

Perpendicular lines have slopes which are negative reciprocals of each other. The slope of the line y=1/2x + 6 is 1/2. The slope perpendicular to it is -2.

Using m=-2, substitute it and (4,-3) into the point slope form and simplify to find the y-intercept.

$y-y_1 = m(x-x_1)\\y--3=-2(x-4)\\y+3=-2(x-4)\\y+3=-2x+8\\y=-2x+5$

The equation is now in slope intercept form y=mx+b and b is the y-intercept. The y-intercept of y=-2x+5 is (0,5).

4 0

3 years ago

Calculate the value of y if -2(3x + 8). + 28 = 0 and -4(x+y) = 2y,

Damm [24]

Answer:

hi Miaxoxo ?

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3 years ago

The amount of time a certain brand of light bulb lasts is normally distribued with a mean of 1300 hours and a standard deviation

Bezzdna [24]

Answer:

The interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.

Step-by-step explanation:

In statistics, the 68–95–99.7 rule, also recognized as the Empirical rule, is a shortcut used to recall that 68%, 95% and 99.7% of the values lie within one, two and three standard deviations of the mean, respectively.

Then,

P (µ - σ < X < µ + σ) = 0.68
P (µ - 2σ < X < µ + 2σ) = 0.95
P (µ - 3σ < X < µ + 3σ) = 0.997

he random variable X can be defined as the amount of time a certain brand of light bulb lasts.

The random variable X is normally distributed with parameters µ = 1300 hours and σ = 90 hours.

Compute the interval of hours that represents the lifespan of the middle 68% of light bulbs as follows:

$P (\mu - \sigma < X < \mu + \sigma) = 0.68\\\\P(1300-90$

Thus, the interval of hours that represents the lifespan of the middle 68% of light bulbs is 1210 hours - 1390 hours.

4 0

2 years ago