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3 years ago

In an expression(8/9) squared (-81)+3/5dividedby-9/10

2 answers:

6 0

If you wanted to calculate it, there it is:
$(\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}$

aliya0001 [1]3 years ago

4 0

Answer: -64.0066666667

(((8\9)squared)*(-81))+(((3\5)\(-9))\10)

Step-by-step explanation:

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What is the equation of the line that passes through the point (-6, -6) and has a slope of - 1/3

pickupchik [31]

Answer:

The equation of the line is $y = -\frac{1}{3}x - 8$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

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This means that $m = -\frac{1}{3}$

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Through the point (-6, -6)

This means that when $x = -6, y = -6$ . So

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3 years ago

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ankoles [38]

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

12/19*.............................= -12/19

melamori03 [73]

Answer:

$\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}$

Step-by-step explanation:

$\frac{12}{19} \times ..... = -\frac{12}{19}$

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= $\frac{12}{19} \times -\frac{19}{12}$

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= $\bold{-1}$

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3 years ago

In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho

Mekhanik [1.2K]

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Additionally, this can be solved by equations:

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$1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} = x$

By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

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3 years ago

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chubhunter [2.5K]

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3 years ago

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