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4 years ago

What is the sum of 2/7 and 5/6?

Mathematics

1 answer:

Tatiana [17]4 years ago

3 0

7/42 because the common multiple of 7 and 6 is 42 and I added the numerator

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HELP PLEASEE AND ANSWER MY OTHER QUESTIONS ASAP 5. Jesse rotated the triangle 90° clockwise about the origin to create figure

Molodets [167]

Answer:

its b cus hit dat hommie

Step-by-step explanation:

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3 years ago

how would a enter a payment that was accepted with a 4 month, 8% note in a payment of a $4800.00 account

Anon25 [30]

Answer:

Enter a payment of 5192.52.

Step-by-step explanation:

Consider the provided information.

The payment is $4800 with a 4 month, 8% note.

The amount can be calculated as:

$Amount=p(1+\frac{r}{m})^{mt}$

Where p is money invested, r is annual interest rate, t is number of years and m is number of period.

Now substitute p = 4800 r = 0.08 and m = 4 in the above formula.

$Amount=4800(1+\frac{0.08}{4})^4$

$Amount=4800(1+0.02)^4$

$Amount=4800(1.02)^4$

$Amount=4800(1.08243216)$

$Amount=5195.52\ approximately$

Hence, enter a payment of 5192.52.

6 0

3 years ago

What is the speaker’s viewWhen I heard the learn'd astronomer;

Phantasy [73]

A. He feels tired and sick because the focus on the mechanical measurements of stars is not satisfying to him.

4 0

3 years ago

A survey of 1250 trees in a small wood showed that 32 percent were oak trees 26 percent were birch trees and the remainder were

timofeeve [1]

Answer: There were 525 pine trees.

Step-by-step explanation:

Given: Total trees = 1250

Percentage of oak trees = 32%

Percentage of birch trees = 26%

Since remaining trees are pine trees.

Percentage of pine trees = 100% - 32% - 26%

=42%

The number of pine trees = 42% of 1250

= 0.42 ×1250

= 525

Hence, there were 525 pine trees.

5 0

3 years ago

1) State the amplitude, period, phase shift, vertical shift and graph

bogdanovich [222]

Answer:

See answers and explanations below (along with a visual graph)

Step-by-step explanation:

For the function $y=acos(b(x+c))+d$ :

Amplitude: $|a|$

Period: $\frac{2\pi}{|b|}$

Phase shift: $\frac{-c}{b}$

Vertical shift: $d$

Therefore, for $y=2cos(\frac{2}{3}(\theta+\pi))-1$ :

Amplitude: $|a|=|2|=2$ , which is 2 units above and below the midline (see d)

Period: $\frac{2\pi}{|b|}=\frac{2\pi}{|\frac{2}{3}|}=\frac{2\pi}{\frac{2}{3}}=3\pi$ , so the cycle will repeat every 3π units

Phase shift: $\frac{-c}{b}=\frac{-\frac{2\pi}{3} }{\frac{2}{3} }=-\pi$ , or π units to the left

Vertical shift: $d=-1$ , or 1 unit down

3 0

3 years ago