You solve an equation like this by adding the opposite of the constant to both sides of the equation.
... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b
... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0
... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V
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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.
Above is postive. So the answer is +300
Answer:
(a)then the product of these two numbers is divisible by 6.
Step-by-step explanation:
If a and b are two integers where at least one of a or b is divisible by 6, the product ab will also be divisible by 6.
If, a is divisible by 6, a/6 = c (an integer).
Product of a and b, (ab)/6 = (a/6) X b =cb.
Likewise if b is divisible by 6, same rule applies.
We only need a term in the product to be divisible by an integer for the product to be divisible by the integer.
Answer:
16+16
32
Step-by-step explanation:
