Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
2x X 54 is going to be 108x
since both are positive you will get a positive #
54 X 2 is 108
Answer:
(0.1,1.1)
Step-by-step explanation:
we have
Solve the system of equations by graphing
The solution is the intersection point both graphs
The solution is the point (0.081,1.093)
see the attached figure
Round to the nearest tenth ----> (0.1,1.1)
9 or -9 ...if I’m wrong sorry
The correct answer that would complete the given statement above would be 59. The measurement of 0.059 seconds is equal to 59 milliseconds. To convert this, you need to know that in every 1 second, there are 1000 milliseconds. And for 1 millisecond, there is 0.001 second.
